How much pure alcohol is in a standard beer serving of 12 oz at 5% alc./vol.?

To determine the amount of pure alcohol in a standard serving of beer, you can use the formula:

Amount of pure alcohol (in ounces) = (Volume of drink in ounces) × (Alcohol by volume percentage / 100).

In this case, the volume of the drink is 12 ounces, and the alcohol by volume (ABV) is 5%.

Calculating this gives:

Amount of pure alcohol = 12 oz × (5 / 100) = 12 oz × 0.05 = 0.6 oz.

Thus, the amount of pure alcohol in a 12 oz beer with 5% alcohol by volume is indeed 0.6 ounces. This calculation aligns with standard practices in measuring alcohol content, making the answer accurate and relevant.